I want to build a GPS timeserver like 

 

http://rdlazaro.info/compu-Raspberry_Pi-RPi-stratum0.html

 

I modified the kernel config to use the pps-gpio module in kernel , but since H3 linux kernel don't support device tree yet, Is there any method to assign a GPIO pin to this module ? I don't want to hard-code in the source code .

Why do you say that H3 doesn't support device tree yet ?

It does, but not using Legacy !

But maybe you mean it doesn't support "overlays" yet ...

whatever，is there any method?

Maybe I can add a pps-gpio section in .dts file in u-boot source?

Yes, that is the way to do, using dtc to decompile/recompile the dtb.

Thank you for your advice.

I plug the GPS module PPS output to OPiOne's GPIO pin PG09,

 

modify fex file to release PG09 from GPIO,

 

and then run gpsd,  PPS worked!  

 

It's very strange, no any device tree setup.

If you're using a fex file then you're using a old kernel 3.4.XXX.

Newer kernel use DT

You're so humor. 

 

The default kernel for Armbian on H3 is 3.4.112 .

 

At last, I found this https://github.com/infinet/bananapi.git , very amazing.

Now, It looks like this :

I do not understand how he did it ...
Can somebody explain?
I would like to repeat it

modify fex file like this:

 

[uart1]

uart_used = 1

uart_port = 1

# 2 for 2-wire

uart_type = 2

uart_tx = port:PG06<2><1><default><default>

uart_rx = port:PG07<2><1><default><default>

 

[gpio_para]

gpio_used = 1

gpio_num = 16

...

#gpio_pin_17 = port:PG09<0><default><default><0>

 

#for UART1

#gpio_pin_18 = port:PG06<1><default><default><default>

#gpio_pin_19 = port:PG07<1><default><default><default>

Thanks for the answer!

With this no problems.
I wanted to know how to assign a pin to PPS?

 

use path https://github.com/infinet/bananapi

as you pointed out the pin?

options pps-gpio gpio_pin=PG09 

or

options pps-gpio gpio_pin=17

o, PG09 is GPIO 201, so 

yaofei@opigps:/etc$ more modprobe.d/pps-gpio.conf
#PG9 = 32*6 + 9 = 201
options pps-gpio gpio_pin=201

Wow

 

What is then the algorithm counting pins?

 

PA = 0

PB = 1

PC = 2

PD = 3

PE = 4

PF = 5

PG = 6

 

Physical pin 18 this PC07 pin H3

PC07 = 32*2 + 7 = 71

This is the correct understanding?

Wow

 

What is then the algorithm counting pins?

 

PA = 0

PB = 1

PC = 2

PD = 3

PE = 4

PF = 5

PG = 6

 

Physical pin 18 this PC07 pin H3

PC07 = 32*2 + 7 = 71

This is the correct understanding?

 

Yeah, you're so smart .

Thank you for your help!